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-x^2+11x+20=0
We add all the numbers together, and all the variables
-1x^2+11x+20=0
a = -1; b = 11; c = +20;
Δ = b2-4ac
Δ = 112-4·(-1)·20
Δ = 201
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-\sqrt{201}}{2*-1}=\frac{-11-\sqrt{201}}{-2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+\sqrt{201}}{2*-1}=\frac{-11+\sqrt{201}}{-2} $
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